0=-16x^2+6x+22

Solution for 0=-16x^2+6x+22 equation:

0=-16x^2+6x+22

We move all terms to the left:

0-(-16x^2+6x+22)=0

We add all the numbers together, and all the variables

-(-16x^2+6x+22)=0

We get rid of parentheses

16x^2-6x-22=0

a = 16; b = -6; c = -22;
Δ = b2-4ac
Δ = -62-4·16·(-22)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-38}{2*16}=\frac{-32}{32}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+38}{2*16}=\frac{44}{32}
=1+3/8
$